Embed widget in android activity - not responding -

-

I am trying to create a home screen. I have got the widget to show the display but I have some kind of Need to send information, so it will start. Maybe me AndroidManifest.xml

AndroidManifest.xml: 

  & lt; Manifest xmlns: android = "http: //schemas.android.com/apk/res/android" package = "com.Fredrik" android: versionCode = "1" Android: versionName = "1.0" & gt; & Lt; Usage-permission Android: name = "android.permission.INTERNET" /> & Lt; Application Android: Icon = "@ Drable / Icon" Android: label = "@ string / app_name" & gt; & Lt; Activity Android: name = "Homescreen" Android: label = "@ string / app_name" Android: launchMode = "Single instance" Android: stateNotNeeded = "true" & gt; & Lt; Intent-Filter & gt; & Lt; Action Android: name = "android.intent.action.MAIN" /> & Lt; Category android: name = "android.intent.category.LAUNCHER" /> & Lt; Category android: name = "android.intent.category.DEFAULT" /> & Lt; / Intent-Filter & gt; & Lt; / Activity & gt; & Lt; / Application & gt; & Lt; / Reveal & gt;   
 Homescreen.Java:  
  Expands the public class home-cycle activity {@Override Creates the Public on Zero (Bundled Saved Instance) {super.onCreate (SavedInstanceState); Final AppWidgetManager Widget = AppWidgetManager GetStation (getApplicationContext ()); & Lt; AppWidgetProviderInfo & gt; Installed Providers = Widgets GetInstalledProviders (); (AppWidgetProviderInfo ws: installProviders) {if (ws.label.startsWith ("Music (Big)")} {AppWidgetHost h = New AppWidgetHost (getApplicationContext (), 10); Int id = h.allocateAppWidgetId (); AppWidgetHostView v = h.createView (this, id, ws); SetContentView (v); H.startListening (); break; }}}   
}  
 Do anyone have a clue?   
 
 
 According to this post, you can not program yourself as a widget entry:  
 You have to make an intentional call that will give the user the ability to choose.  
 I was still surprised to hear that you managed to show it ...

Comments

Post a Comment

Popular posts from this blog

qt - switch/case statement in C++ with a QString type -

-
I want to use switch-case in my program but the compiler generates an error. How can I use the switch statement with QString ? The compiler gives me this error: The expression of the switch type 'QString' is invalid My code is as follows : boolStopWord (the word QString) {bool flag = false; Switch (word) {case "the": flag = true; break ; "On" case: flag = true; break ; Case "in": flag = true; break ; Case "your": flag = true; break ; Case "near": flag = true; break ; Case "all": flag = true; break ; Case "this": flag = true; break ; } Return flag; } How do I use the switch statement with a Caststring ? You can not use the switch statement in C ++ language with integral or enum types. You can formally enter the square type of object in the switch statement, but this means that the compiler will look for a user-defined conversion to convert it to an integral or enum type.
Read more

python - sqlite3.OperationalError: near "REFERENCES": syntax error - foreign key creating -

-
I'm trying to create a predefined key after checking the manual and I wrote it: Db.execute ("create table" Table 2 (id, integer primary key, somedata integer) "db.execute" (table creation table 2 does not exist (name text, maintain reference (id) ") and found this: sqlite 3. Operation error: near" references ": syntax error Your second ligne is wrong db.execute ("create table if table does not exist 2 (name text, my_id integer, foreign key (my_id) reference Maintenance (ID)) ") as explained
Read more

Python's equivalent for Ruby's define_method? -

-
What is a Python equivalent for Ruby's define_method , which is the dynamic generation of class methods will allow? (As can be seen in Wikipedia) Functions are first-class objects in Python and assign them The properties of a class or an example can be a way of doing the same thing as a Wikipedia example: colors = {"black": "000", "red": "F00", "green": "0f0", "yellow": "ff0", "blue": "00f", "magenta": "fff", "cyan": "0ff", "white": " FFF "} Class MyStream (ARR): Pass for Name, Code in colors.iteritems (): def _in_colour ( W code = code): return '& lt; Span style = "color:% s" & gt;% s & lt; / Span & gt; ' % (Code, self) setter (histrive, "in_" + name, _in_ color)
Read more