CSS :not(:last-child):after selector -

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मेरे पास तत्वों की एक सूची है: 

  & lt; ul & gt; & Lt; li & gt; एक & lt; / li & gt; & Lt; li & gt; दो & lt; / li & gt; & Lt; li & gt; तीन & lt; / li & gt; & Lt; li & gt; चार & lt; / li & gt; & Lt; li & gt; पांच & lt; / li & gt; & Lt; / ul & gt;   
 और इस तरह स्टाइल:  
  ul {list-style-type: none; पाठ संरेखित करें: केंद्र; } ली {प्रदर्शन: इनलाइन; } Li: नहीं (: अंतिम-बच्चा): {content: '|'; }   
 आउटपुट  वन | दो | तीन | चार | पांच |  के बजाय  एक | दो | तीन | चार | पांच   
 किसी को पता है कि कैसे सीएसएस सभी का चयन लेकिन पिछले तत्व?  
 आप  की परिभाषा देख सकते हैं: नहीं ()  चयनकर्ता   
 
 
 यदि यह चयनकर्ता के साथ कोई समस्या है, तो आप उन सभी को सेट कर सकते हैं और पिछले एक को ओवरराइड कर सकते हैं < / P> 
  li: के बाद {सामग्री: '|'; } Li: अंतिम बच्चा: {content: ''; }   
 या यदि आप पहले उपयोग कर सकते हैं, आखिरी बच्चे के लिए कोई ज़रूरत नहीं है  
  li + li: पहले {content: '| '; }

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