php - selecting value from drop down dropdown -

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Hello, I am going to edit the drop down box value, how do I show values ​​from the previous database like V 

  `< Input name = "initial" size = "8" value = "& lt ;? php resonant $ res ['beginners'] ;? & gt;" / `& gt;   
 So how can I do this code for this  
  & lt; Select name = "employee_id" id = "employee_id" & gt; & Lt; Option value = "" & gt; Select & lt; / Options & gt; & Lt ;? Php $ Task = new task (); $ Task- & gt; Connect (); Echoes $ emp = $ work- & gt; GetEmployee (); $ Task- & gt; Disconnect (); ? & Gt; & Lt; / Select & gt; Function getEmployee () {$ this- & gt; Query = ("select from employee"); $ Rd = $ this- & gt; ExecuteQuery (); While ($ line = mysqli_fetch_assoc ($ rd)) {$ pno = $ row ['pno']; $ Name = $ line ['name']; Echo "& lt; option value = '$ pno' & gt; $ name & lt; / option & gt;"; }}}   
 If I place it here in the value value then it will be considered as one but it will not show in the drop down box. So in a nutshell, this assumes from the array and shows in the dropdown box   
 
 
 This selects your desired value Will your dropdown list  
  echo "& lt; option value = '$ pno'". ($ Pno == $ picker? "Selected = 'selected'": ""). "& Gt; $ name & lt; / options & gt;";

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