JPA one to many map key -

-

मेरे पास निम्न है 

  @OneToMany (मैप किए गए = "भूमिका") @मैकेके ( Name = "role.name") निजी मानचित्र & lt; स्ट्रिंग, यूज़ररोल & gt; UserRoles = नया हैशमॉप & lt; स्ट्रिंग, यूज़ररोल & gt; ();   
 मैं मानचित्र के लिए कुंजी के रूप में UserRole में भूमिका ऑब्जेक्ट के नाम विशेषता का उपयोग करना चाहता हूं, मैं यह कैसे प्राप्त कर सकता हूं। @MapKey (name = "role.name") काम नहीं करता है  
 मेरे UserRole.java में निम्न है  
  @ManyToOne @JoinColumn (name = "roleId") निजी भूमिका भूमिका; जेपीए में @ मैकेकी केवल एक स्थानीय क्षेत्र ही हो सकता है।    
 
 
 यदि आप ईक्लिप्स लिंक उपयोग कर रहे हैं तो आप मैप कुंजी के रूप में एक विधि का भी उपयोग कर सकते हैं, ताकि आप UserRole में एक getRoleName () को परिभाषित कर सकता है जो भूमिका का नाम देता है, और इसका उपयोग @MapKey के साथ करें।

Comments

Post a Comment

Popular posts from this blog

qt - switch/case statement in C++ with a QString type -

-
I want to use switch-case in my program but the compiler generates an error. How can I use the switch statement with QString ? The compiler gives me this error: The expression of the switch type 'QString' is invalid My code is as follows : boolStopWord (the word QString) {bool flag = false; Switch (word) {case "the": flag = true; break ; "On" case: flag = true; break ; Case "in": flag = true; break ; Case "your": flag = true; break ; Case "near": flag = true; break ; Case "all": flag = true; break ; Case "this": flag = true; break ; } Return flag; } How do I use the switch statement with a Caststring ? You can not use the switch statement in C ++ language with integral or enum types. You can formally enter the square type of object in the switch statement, but this means that the compiler will look for a user-defined conversion to convert it to an integral or enum type.
Read more

python - sqlite3.OperationalError: near "REFERENCES": syntax error - foreign key creating -

-
I'm trying to create a predefined key after checking the manual and I wrote it: Db.execute ("create table" Table 2 (id, integer primary key, somedata integer) "db.execute" (table creation table 2 does not exist (name text, maintain reference (id) ") and found this: sqlite 3. Operation error: near" references ": syntax error Your second ligne is wrong db.execute ("create table if table does not exist 2 (name text, my_id integer, foreign key (my_id) reference Maintenance (ID)) ") as explained
Read more

Python's equivalent for Ruby's define_method? -

-
What is a Python equivalent for Ruby's define_method , which is the dynamic generation of class methods will allow? (As can be seen in Wikipedia) Functions are first-class objects in Python and assign them The properties of a class or an example can be a way of doing the same thing as a Wikipedia example: colors = {"black": "000", "red": "F00", "green": "0f0", "yellow": "ff0", "blue": "00f", "magenta": "fff", "cyan": "0ff", "white": " FFF "} Class MyStream (ARR): Pass for Name, Code in colors.iteritems (): def _in_colour ( W code = code): return '& lt; Span style = "color:% s" & gt;% s & lt; / Span & gt; ' % (Code, self) setter (histrive, "in_" + name, _in_ color)
Read more