c# windows service process.start -

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मैंने एक विंडो सेवा बनाई है मैं ओन्स्टार्ट (स्ट्रिंग [] आर्गेंस] विधि में प्रक्रिया। स्टार्ट - दूसरे एक्जिक्यूटिव को खोलने के लिए इस्तेमाल कर सकता हूं। क्या यह काम करेगा? मैं एक विंडोज सर्विस एप्लीकेशन बनाना चाहता हूं जो एक निष्पादन योग्य फ़ाइल खोलता है (खराब उदाहरण सीएमडी जहां मैं नोटपैड फ़ाइल खोलने के लिए अपना खुद का आदेश जोड़ सकता हूं।

< P> आपको सेवा को डेस्कटॉप (सेवा एमजीआर में सेवा प्रॉपर्टी के अंतर्गत) के साथ इंटरैक्ट करने की अनुमति मिलनी होगी, लेकिन कभी-कभी इसे बुरा माना जाता है। ध्यान दें, इसके कारण विंडोज 2008 और इसके बाद के संस्करण में इसे मुश्किल बना दिया गया है।

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