iphone - How can I know the values in CABasicAnimation keyPath -

-

मुझे कुछ कोड ऐसा लगता है: 

  सीएबीएसीएसीएनिमेशन * एनीम = [कैबैसिकएनिमेशन एनीमेशन]; Anim.keyPath = @ "ट्रांसफॉर्म। स्केल"; Anim.fromValue = [एनएसएनम्बर नंबरएफ़्लोएटः 1.0]; Anim.toValue = [एनएसएनम्बर नंबरएफ़्लोएटः 0]; Anim.removedOnCompletion = नहीं; Anim.fillMode = kCAFillModeBoth; Anim.delegate = self; [Self.view.layer addAnimation: एनिम forKey: @ "scaleOut"];   
 और  
  anim.keyPath = @ "transform.rotation.x";   
 जहाँ तक मुझे पता है, keypath एक जंजीर विधि आह्वान है। CALayer के लिए "transform.scale" एक aLayer.transform.scale है। "परिणत" कैलायर की संपत्ति है, "स्केल" ट्रांसफॉर्मेशन की एक 'प्रॉपर्टी' है लेकिन CALayer में संपत्ति परिणत CATransform3D है।  
 CATransform3D में "स्केल" या "रोटेशन" नामक संपत्ति नहीं है  
 मेरा प्रश्न यह है कि "पैमाना" और "रोटेशन" किस पैड से पहचाने जाते हैं?   
 
 
 कोर एनीमेशन परतों के कुछ स्ट्रेट-प्रकार गुणों के खेतों (या छद्म क्षेत्रों) के सीधे संबोधन में सहायता के लिए केवीसी तक फैली हुई है। फीचर में वर्णित है।

Comments

Post a Comment

Popular posts from this blog

qt - switch/case statement in C++ with a QString type -

-
I want to use switch-case in my program but the compiler generates an error. How can I use the switch statement with QString ? The compiler gives me this error: The expression of the switch type 'QString' is invalid My code is as follows : boolStopWord (the word QString) {bool flag = false; Switch (word) {case "the": flag = true; break ; "On" case: flag = true; break ; Case "in": flag = true; break ; Case "your": flag = true; break ; Case "near": flag = true; break ; Case "all": flag = true; break ; Case "this": flag = true; break ; } Return flag; } How do I use the switch statement with a Caststring ? You can not use the switch statement in C ++ language with integral or enum types. You can formally enter the square type of object in the switch statement, but this means that the compiler will look for a user-defined conversion to convert it to an integral or enum type.
Read more

python - sqlite3.OperationalError: near "REFERENCES": syntax error - foreign key creating -

-
I'm trying to create a predefined key after checking the manual and I wrote it: Db.execute ("create table" Table 2 (id, integer primary key, somedata integer) "db.execute" (table creation table 2 does not exist (name text, maintain reference (id) ") and found this: sqlite 3. Operation error: near" references ": syntax error Your second ligne is wrong db.execute ("create table if table does not exist 2 (name text, my_id integer, foreign key (my_id) reference Maintenance (ID)) ") as explained
Read more

Python's equivalent for Ruby's define_method? -

-
What is a Python equivalent for Ruby's define_method , which is the dynamic generation of class methods will allow? (As can be seen in Wikipedia) Functions are first-class objects in Python and assign them The properties of a class or an example can be a way of doing the same thing as a Wikipedia example: colors = {"black": "000", "red": "F00", "green": "0f0", "yellow": "ff0", "blue": "00f", "magenta": "fff", "cyan": "0ff", "white": " FFF "} Class MyStream (ARR): Pass for Name, Code in colors.iteritems (): def _in_colour ( W code = code): return '& lt; Span style = "color:% s" & gt;% s & lt; / Span & gt; ' % (Code, self) setter (histrive, "in_" + name, _in_ color)
Read more